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Maths Quantitative Aptitude Questions Answers
1. A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
A. 45%
B. 45 5/11%
C. 54 6/11%
D. 55%
Answer: Option B
Explanation:
Number of runs made by running = 110 – (3 x 4 + 8 x 6)
= 110 – (60)
= 50.
Required percentage = 50 /110 x 100 % = 45 5 /11%
Q:2 In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was :
A) 2500 B) 2700
C) 2900 D) 3100
Answer & ExplanationAnswer: B) 2700
Explanation:
Total number of votes = 7500
Given that 20% of Percentage votes were invalid
=> Valid votes = 80%
Total valid votes = 7500*(80/100)
1st candidate got 55% of the total valid votes.
Hence the 2nd candidate should have got 45% of the total valid votes
=> Valid votes that 2nd candidate got = total valid votes x (45/100)
7500*(80/100)*(45/100) = 2700
Q3:If 20% of a = b, then b% of 20 is the same as :
A) 4% of a B) 6% of a
C) 8% of a D) 10% of a
Answer & ExplanationAnswer: A) 4% of a
Explanation:
20% of a = b
=> (20/100) * a = b
b% of 20 =(b/100) x 20 = [(20a/100) / 100] x 20= 4a/100 = 4% of a.
Q4: Fresh fruit contains 68% water and dry fruit contains 20% water. How much dry fruit can be obtained from 100 kg of fresh fruits?
A) 20 B) 30
C) 40 D) 50
Answer & ExplanationAnswer: C) 40
Explanation:
The fruit content in both the fresh fruit and dry fruit is the same.
Given, fresh fruit has 68% water.so the remaining 32% is fruit content. weight of fresh fruits is 100kg
Dry fruit has 20% water.so the remaining 80% is fruit content. let weight if dry fruit is y kg.
Fruit % in freshfruit = Fruit% in dryfruit
Therefore, (32/100) x 100 = (80/100 ) x y
we get, y = 40 kg.
Q: A student multiplied a number by 3/5 instead of 5/3, What is the percentage error in the calculation?
A) 54 % B) 64 %
C) 74 % D) 84 %
Answer & ExplanationAnswer: B) 64 %
Explanation:
Let the number be x.
Then, ideally, he should have multiplied by x by 5/3. Hence Correct result was x * (5/3)= 5x/3.
By mistake, he multiplied x by 3/5. Hence the result with error = 3x/5
Then, error = (5x/3 – 3x/5) = 16x/15
Error % = (error/True vaue) * 100 = [(16/15) * x/(5/3) * x] * 100 = 64 %
