Math Formula PDF in Hindi 2022-23
Math Formula In Hindi {गणित के प्रश्नो को हल करने का सबसे आसान ट्रिक} :- We all know that math subjects and math questions are very important for all types of exams and at the same time Math formula in hindi pdf for Competitive exams 2022 is also very important, so today we are here for you All Maths Formulas PDF in Hindi download for you. This All Math Formula in Hindi PDF Download 2022-23 It will help you a lot in solving all types of questions of exams and improve your preparation of upcoming government exams like SSC CGL, BANK, RAILWAYS, RRB NTPC, LIC AAO, and many other exams.
pdfdownload.in is an online free study provide educational website, where we are sharing free of cost pdf of All Mathematics Formula In Hindi {** गणित सूत्र PDF में पढ़े. **} for all competitive exams and many other exams. Our math Questions is very simple and easy to understand. We also cover basic subjects like Mathematics, Geography, History, General Science, Politics, etc. We also share study material including previous year question papers, current affairs, important sources, etc. for upcoming government exams. Our Mathematics Formula PDF for Competitive Exam in Hindi PDF will help you prepare for any SARKARI EXAM.
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Important Maths Formula For You
- प्राकृतिक संख्या (Natural Numbers) – an – bn = (a – b)(an-1 + an-2 +…+ bn-2a + bn-1)
- सम संख्या (Even) – (n = 2k), an + bn = (a + b)(an-1 – an-2b +…+ bn-2a – bn-1)
- विषम संख्या (Odd) – (n = 2k + 1), an + bn = (a + b)(an-1 – an-2b +…- bn-2a + bn-1)
- (a + b + c + …)2 = a2 + b2 + c2 + … + 2(ab + ac + bc + ….
- घातांक के नियम (Low Of Formula Exponents)
- 1. (am)(an) = am+n
- 2. (ab)m = ambm
- 3. (am)n = amn
- a2 – b2 = (a – b)(a + b)
- (a+b)2 = a2 + 2ab + b2
- a2 + b2 = (a – b)2 + 2ab
- (a – b)2 = a2 – 2ab + b2
- (a + b + c)2 = a2 + b2 + c2 + 2ab + 2ac + 2bc
- (a – b – c)2 = a2 + b2 + c2 – 2ab – 2ac + 2bc
- (a + b)3 = a3 + 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b)
- (a – b)3 = a3 – 3a2b + 3ab2 – b3
- a3 – b3 = (a – b)(a2 + ab + b2)
- a3 + b3 = (a + b)(a2 – ab + b2)
- (a + b)3 = a3 + 3a2b + 3ab2 + b3
- (a – b)3 = a3 – 3a2b + 3ab2 – b3
- (a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4)
- (a – b)4 = a4 – 4a3b + 6a2b2 – 4ab3 + b4)
- a4 – b4 = (a – b)(a + b)(a2 + b2)
- a5 – b5 = (a – b)(a4 + a3b + a2b2 + ab3 + b4)
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