
Math Formula In Hindi PDF Download
Math Formula pdf in Hindi For All Competitive Exams 2022-23:- Today, we are sharing the All Maths Formulas PDF in Hindi download for you. This Math formula in hindi pdf for Competitive exams 2021 can prove to be important for the preparation of upcoming government exams like SSC CGL, BANK, RAILWAYS, RRB NTPC, LIC AAO, and many other exams. Mathematics notes are very important for any Sarkari exam.
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pdfdownload.in is an online educational website, where we are sharing Math Formula In Hindi {गणित के प्रश्नो को हल करने का सबसे आसान ट्रिक} for free DOWNLOAD for UPSC, SSC, BANK, RAILWAY, LIC, and many other exams. Our General Science Questions PDF is very simple and easy to understand. We also cover basic subjects like Mathematics, Geography, History, General Science, Politics, etc. We also share study material including previous year question papers, current affairs, important sources, etc. for upcoming government exams. Our PDF will help you prepare for any SARKARI EXAM.
Download GK Notes
- सम्पूर्ण जिव विज्ञान की बुक डाउनलोड करे हिंदी में
- रेलवे की सम्पूर्ण बुक एग्जाम की तैयारी करे बड़ी आसानी से
- रेलवे अस्सिस्टेंट लोको पायलट एवं टेक्निशन की सम्पूर्ण बुक डाउनलोड करे
- सम्पूर्ण जिव विज्ञान की बुक डाउनलोड करे हिंदी में
- भारतीय भूगोल के शानदार प्रश्नोत्तर सभी कम्पीटीशन एग्जाम के लिए महत्वपूर्ण
- GK Questions In Hindi PDF Download
Important Maths Formula
- प्राकृतिक संख्या (Natural Numbers) – an – bn = (a – b)(an-1 + an-2 +…+ bn-2a + bn-1)
- सम संख्या (Even) – (n = 2k), an + bn = (a + b)(an-1 – an-2b +…+ bn-2a – bn-1)
- विषम संख्या (Odd) – (n = 2k + 1), an + bn = (a + b)(an-1 – an-2b +…- bn-2a + bn-1)
- (a + b + c + …)2 = a2 + b2 + c2 + … + 2(ab + ac + bc + ….
- घातांक के नियम (Low Of Formula Exponents)
- 1. (am)(an) = am+n
- 2. (ab)m = ambm
- 3. (am)n = amn
- a2 – b2 = (a – b)(a + b)
- (a+b)2 = a2 + 2ab + b2
- a2 + b2 = (a – b)2 + 2ab
- (a – b)2 = a2 – 2ab + b2
- (a + b + c)2 = a2 + b2 + c2 + 2ab + 2ac + 2bc
- (a – b – c)2 = a2 + b2 + c2 – 2ab – 2ac + 2bc
- (a + b)3 = a3 + 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b)
- (a – b)3 = a3 – 3a2b + 3ab2 – b3
- a3 – b3 = (a – b)(a2 + ab + b2)
- a3 + b3 = (a + b)(a2 – ab + b2)
- (a + b)3 = a3 + 3a2b + 3ab2 + b3
- (a – b)3 = a3 – 3a2b + 3ab2 – b3
- (a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4)
- (a – b)4 = a4 – 4a3b + 6a2b2 – 4ab3 + b4)
- a4 – b4 = (a – b)(a + b)(a2 + b2)
- a5 – b5 = (a – b)(a4 + a3b + a2b2 + ab3 + b4)
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