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**One Liner Related Maths Quantitative Aptitude Book**

- Rekha is the most appropriate method of teaching mathematics. – Arrival method
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**Maths Quantitative Aptitude Questions Answers**

**1.** A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?

A. 45%

B. 45 5/11%

C. 54 6/11%

D. 55%

**Answer: Option B**

**Explanation:**

**Number of runs made by running = 110 – (3 x 4 + 8 x 6)**

**= 110 – (60)**

**= 50.**

** Required percentage = ****50 /110 x 100 % = 45 5 /11%**

Q:2 In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was :

A) 2500 B) 2700

C) 2900 D) 3100

** Answer & ExplanationAnswer: B) 2700**

**Explanation:**

**Total number of votes = 7500 **

**Given that 20% of Percentage votes were invalid**

** => Valid votes = 80%**

** Total valid votes = 7500*(80/100) **

**1st candidate got 55% of the total valid votes. **

**Hence the 2nd candidate should have got 45% of the total valid votes **

**=> Valid votes that 2nd candidate got = total valid votes x (45/100) **

**7500*(80/100)*(45/100) = 2700**

**Q3:If 20% of a = b, then b% of 20 is the same as :**

A) 4% of a B) 6% of a

C) 8% of a D) 10% of a

** Answer & ExplanationAnswer: A) 4% of a**

**Explanation:**

**20% of a = b **

**=> (20/100) * a = b **

**b% of 20 =(b/100) x 20 = [(20a/100) / 100] x 20= 4a/100 = 4% of a.**

**Q4: Fresh fruit contains 68% water and dry fruit contains 20% water. How much dry fruit can be obtained from 100 kg of fresh fruits?**

A) 20 B) 30

C) 40 D) 50

** Answer & ExplanationAnswer: C) 40**

**Explanation:**

**The fruit content in both the fresh fruit and dry fruit is the same.**

**Given, fresh fruit has 68% water.so the remaining 32% is fruit content. weight of fresh fruits is 100kg**

**Dry fruit has 20% water.so the remaining 80% is fruit content. let weight if dry fruit is y kg.**

**Fruit % in freshfruit = Fruit% in dryfruit **

**Therefore, (32/100) x 100 = (80/100 ) x y **

**we get, y = 40 kg.**

**Q: A student multiplied a number by 3/5 instead of 5/3, What is the percentage error in the calculation?**

A) 54 % B) 64 %

C) 74 % D) 84 %

** Answer & ExplanationAnswer: B) 64 %**

**Explanation:**

**Let the number be x.**

**Then, ideally, he should have multiplied by x by 5/3. Hence Correct result was x * (5/3)= 5x/3. **

**By mistake, he multiplied x by 3/5. Hence the result with error = 3x/5 **

**Then, error = (5x/3 – 3x/5) = 16x/15 **

**Error % = (error/True vaue) * 100 = [(16/15) * x/(5/3) * x] * 100 = 64 %**