Basic Mathematics & Measurements Notes pdf in English

Basic Mathematics & Measurements Notes pdf in English

Basic Mathematics & Measurements Notes pdf in English

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Basic Mathematics & Measurements Notes pdf in English :-  We all know that math subject is the most important subject for our all government job exams so today, we are sharing easy and important the Basic Mathematics & Measurements Notes pdf in English Free for your math exams score improvement. This Basic Mathematics & Measurements books for competitive exams pdf free download Download for the preparation of upcoming government exams like SSC CGL, BANK, RAILWAYS, RRB NTPC, LIC AAO, and many other exams. Math Book pdf Download For Competitive Exams 2022-23.

pdfdownload.in is an online educational website, where we are sharing Basic Mathematics & Measurements Notes pdf in English for free DOWNLOAD for UPSC, SSC, BANK, RAILWAY, LIC, and many other exams. Our Best Maths Book and Notes PDF Download for All Competitive Exams | गणित बुक एवं नोट्स पीडीएफ़ डाउनलोड करे is very simple and easy to understand. We also cover basic subjects like Mathematics, Geography, History, General Science, Politics, etc. We also share study material including previous year question papers, current affairs, important sources, etc. for upcoming government exams. Our PDF will help you prepare for any SARKARI EXAM.

Here you are being provided this math book for competitive exams in best quality pdf download for free, which you can download by clicking on the DOWNLOAD button given below, as well as we will give you some question answers related to this PDF Download The Basic Mathematics & Measurements Notes pdf in English  help you in the exams and Other PDF’s are also on this which you can download Comments. You can know about all the new updates on PDFDOWNLOAD.IN by clicking on the Allow button on the screen By which you will get all kinds of new updates for your bright future.

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Measurement Questions and Answers

Q 1. Calculate the sum of lengths: 21 m 13 cm, 33 m 55 cm and 45 m 6 cm.

Solution:

21 m 13 cm + 33 m 55 cm + 45 m 6 cm

= (21 + 33 + 45) m (13 + 55 + 6) cm

= 99 m 74 cm

Therefore, the sum of given lengths = 99 m 74 cm.

Q 2. Beena bought 3 kg 760 grams of wool to make a carpet. How much more wool does she need to make the weight 4 kg?

Solution:

Given the weight of wool = 3 kg 760 grams

Let us convert this weight into grams.

Q 3 kg 760 grams = (3 × 1000 + 760) grams

= (3000 + 760) grams

= 3760 grams

4 kg = (4 × 1000) grams = 4000 grams

Difference = (4000 – 3760) grams = 240 grams

Therefore, 240 grams of more wool is required.

Q 3. A pile of 10 books is 10 cm high. What is the thickness of each book?

Solution:

As we know,

1 cm = 10 mm

Given that the height of a pile of 10 books = 10 cm

10 books = 10 cm

= 10 x 10 mm

= 100 mm

1 book = 100/10

= 10 mm

Therefore, the thickness of each book = 10 mm.

Q 4. A furlong is a unit of length used in horse racing; it equals one-eighth of a mile. To the nearest tenth, how many metres are equal to a furlong if 1.609 km equals a mile?

Solution:

Given,

1.609 km = 1 mile

That means 1609 m = 1 mile

Also, one furlong = one-eighth of a mile

= (1/8) × 1.609 km

= (1/8) × 1609 m

= 201.125

= 201.1 m (approx)

Q 5. The cost of 1 litre of syrup is Rs. 840.80. Find the cost of 600 ml of the syrup.

Solution:

Given,

The cost of 1 litre of syrup = Rs. 840.80

As we know,

1 litre = 1000 ml

The cost of 600 ml of the syrup = (600/1000) × Rs. 840.80 = Rs. 504.48

Q 6. One inch equals 2.54 centimetres. How many centimetres tall is an 84-inch door?

Solution:

Given,

1 inch = 2.54 cm

84 inch = ?

84 inch = 84 × 2.54 cm

= 213.36 cm

Thus, the door is 213.36 cm tall.

Q 7. Vinu and Shan together weigh 72 kg 350 g. If Vinu weighs 39 kg 185 g, what is Shan’s weight?

Solution:

Given,

Vinu’s weight = 39 kg 185 g

Let x be Shan’s weight.

According to the given,

39 kg 185 g + x = 72 kg 350 g

x = 72 kg 350 g – 39 kg 185 g

= (72 – 39) kg (350 – 185) g

= 33 kg 165 g

Therefore, Shan’s weight is 33 kg 165 g.

Q 8. A tabletop measures 2 m 25 cm by 1 m 50 cm. What is the perimeter of the tabletop?

Solution:

We know that,

1 m = 100 cm

1 cm = 0.01 m

Length of tabletop = 2 m 25 cm = 2.25 m

Breadth of tabletop = 1 m 50 cm = 1.50 m

Perimeter of tabletop = 2 (Length + Breadth)

= 2 (2.25 + 1.50)

= 2 (3.75)

= 2 × 3.75

= 7.5 m

Therefore, the perimeter of the tabletop is 7.5 m.

Q 9. Two sides of a triangle are 11 cm and 15 cm. If the perimeter of the triangle is 36 cm, find its third side.

Solution:

Let x cm be the third side of the triangle.

Given,

Two sides: 11 cm and 15 cm

Perimeter of triangle = 36 cm

11 + 15 + x = 36

26 + x = 36

x = 36 – 26

x = 10 cm

Hence, the third side of the triangle is 10 cm.

Q 10. The weight of a rice packet is 40 kg 360 g. What is the total weight of 6 rice packets of the same weight?

Solution:

Given,

Weight of a rice packet = 40 kg 360 g

Number of rice packets = 6

Total weight = 6 × weight of one rice packet

= 6 × (40 kg 360 g)

= (6 × 40) kg (6 × 360) g

= 240 kg 2160 g

= 240 kg (2000 + 160) g

= (240 + 2) kg 160 g

= 242 kg 160 g

Thus, the total weight of 6 rice packets = 242 kg 160 g.

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Measurement Questions

Measurement is the basic concept that everyone deals with in real-life situations. For instance, we generally use tonnes, kg, and g weights to purchase fruits or vegetables. When we purchase 5 kg of fruits, 5 represents the measurement and kg denotes the unit of measurement.

What is Measurement?

Measurement is the technique of finding a number that signifies the amount, quantity, and size of a thing or object. For example, the length of an object is the distance from end to end. Some basic measurements are:

Length or distance
Weight
Time
Area
Volume
Perimeter
Temperature
Learn more about measurement in maths here.

NCERT Solutions For Class  Maths Chapter 10 Mensuration is an important resource for students to prepare the topic of Mensuration. In exams, several questions are asked from this section, making it one of the most crucial chapters of Class Maths subject. Practising the NCERT Solutions for Class Maths will help the students in understanding the concepts in a better way.

Mathematics is a high scoring subject. Securing high marks in this subject will largely improve the overall aggregate for students. To help students achieve the maximum marks in examinations, individual subject experts at pdfdownload.in have created the NCERT Solutions following the latest CBSE guidelines. Students can access these solutions in both online and offline modes at any time and anywhere.

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